![I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic](https://useruploads.socratic.org/GElC3TZCSVu1KUh19XCf_lateximg.png)
I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic
Find the sum of the following. (1-1/n) + (1-2/n) + (1-3/n) + ....... up to n terms. - Sarthaks eConnect | Largest Online Education Community
![I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic](https://useruploads.socratic.org/IJNGAZ1qQGmjuJYFPCa5_lateximg.png)
I don't understand this explanation for \sum_(n=0)^\infty((-1)^n)/(5n-1)? Why test for convergence/divergence AGAIN, if the Limit Comparison Test confirms that both series are the same? | Socratic
![convergence divergence - Find the sum of the series $\sum_{n=1 }^{\infty}\frac{3n+2}{n!}$ - Mathematics Stack Exchange convergence divergence - Find the sum of the series $\sum_{n=1 }^{\infty}\frac{3n+2}{n!}$ - Mathematics Stack Exchange](https://i.stack.imgur.com/MULIu.jpg)
convergence divergence - Find the sum of the series $\sum_{n=1 }^{\infty}\frac{3n+2}{n!}$ - Mathematics Stack Exchange
![calculus - Determine whether the series $ \ \sum_{n=1}^{\infty} (-1^n) (1 - \frac{1}{n})^{n^2} $ converges absolutely, or converges conditionally, or diverges. - Mathematics Stack Exchange calculus - Determine whether the series $ \ \sum_{n=1}^{\infty} (-1^n) (1 - \frac{1}{n})^{n^2} $ converges absolutely, or converges conditionally, or diverges. - Mathematics Stack Exchange](https://i.stack.imgur.com/iL6nI.jpg)